LeetCode Reverse Bits

Problem

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up: If this function is called many times, how would you optimize it?

即将整数的32个bit，逆序后，输出对应的整数。

Python3

# Reverse bits of a given 32 bits unsigned integer.
#
# For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
#
# Follow up:
# If this function is called many times, how would you optimize it?

# author li.hzh
class Solution:
    # @param n, an integer
    # @return an integer
    def reverseBits(self, n):
        result = 0
        digits = 0
        while digits < 32:
            temp = n & 1
            result <<= 1
            result |= temp
            n >>= 1
            digits += 1
        return result

solution = Solution()
print(solution.reverseBits(43261596))

分析

通过位运算取整移位。不得不说，算是自己的一个进步吧，能应用位运算了。

所有代码已上传至Github：https://github.com/lihongzheshuai/yummy-code

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